Computer Science 210
Data Structures
Fall 2018, Siena College
Powers BlueJ Project
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Powers Source Code
The Java source code for Powers is below. Click on a file name to download it.
import java.util.Scanner; /* * Example Powers: examples of recursive methods to compute * powers of a number. * * Jim Teresco, The College of Saint Rose, CSC 252, Fall 2013 * Updated for CSIS 210, Siena College, Fall 2016, Fall 2018 * */ public class Powers { public static void main(String args[]) { // read in the base and exponent from a Scanner Scanner s = new Scanner(System.in); System.out.println("Let's compute the value of some integer raised to a power."); System.out.print("First, enter the base: "); int base = s.nextInt(); int exponent = 0; do { System.out.print("Next, enter the exponent (>=0): "); exponent = s.nextInt(); if (exponent < 0) { System.out.println("Negative exponents are not allowed"); } } while (exponent < 0); // now we compute in three different ways, using the methods below. System.out.println("" + base + "^" + exponent + ", computed three ways:"); System.out.println("Method using a loop: " + loopPower(base, exponent)); System.out.println("Method using straightforward recursion: " + recPower(base, exponent)); System.out.println("Method using smarter recursion: " + fastRecPower(base, exponent)); } // compute the power using a good old fashioned loop public static int loopPower(int a, int n) { int answer = 1; for (int i = 0; i < n; i++) { answer *= a; } return answer; } // the straightforward recursive approach public static int recPower(int a, int n) { // our base case is n == 0 if (n == 0) { return 1; } // otherwise, we have to do some work, a^n = a * a^{n-1} return a * recPower(a, n -1); } // a more efficient recursive approach, based on the idea // that we can compute a power a^{2n} as (a*a)^n public static int fastRecPower(int a, int n) { // base case is again n == 0 if (n == 0) { return 1; } // now, see if n is even or odd if (n % 2 == 1) { // it's odd, so use straightforward recursion to get // down to an even case return a * fastRecPower(a, n - 1); } // if we got here, it's even, so we can do better return fastRecPower(a * a, n / 2); } }